Need script to log off all sessions for particular pool

[Varozza]

I feel like this should be easy but for some reason I cannot figure this one out. I need a simple script that will identify all open Horizon sessions from a given pool and then logoff each of those sessions. I would like to schedule this to run once daily at the time which that pools users should be out of office to ensure no sessions remain running.

Thanks in advance,

[LucD]

Did you try the code Wouter showed in Pulling horizon session information using PowerCLI and [API]How to successfully logoff users in Horizon?

[Magneet]

^^ this, mainly the second post has a good script for this. Make sure to force the logoff otherwise disconnected sessions won't be logged off.

[Varozza]

Thanks for replies. Sorry, I really just cant seem to grasp the API calls for Horizon. I do this kind of stuff daily for AD with PS commands such as get-aduser, set-aduser, etc. For some reason this one is just evading my understanding.

Thanks to the references given above I have almost got what I need. The script below is working perfectly for identifying the VDI sessions I wish to log off. It seems all I am missing is a one liner to log each of the sessions off as they are found? Any advice how to do this?

$sessions=(get-hvlocalsession).namesdata

foreach ($session in $sessions){

if($session.DesktopName -eq "TESTPOOL1"){

     Write-Host "Connection to TESTPOOL1 found: "  $session.Username 

     #NEED HELP HERE.... NEED TO ADD LOGOFF COMMAND HERE TO LOG OFF THE SESSION IN QUESTION

}

   }

[Magneet]

$hvserver=connect-hvserver servername

$hvservice=$hvserver.extensiondata

$hvservice.session.session_logoff($sessionid)

if you have more sessions.Session_LogoffSessions($arrayodsessionids)

or when they are disconnected/screen locked use Session_LogoffSessionsForced or Session_LogoffForced

or see: https://www.retouw.nl/2019/07/15/apihow-to-successfully-logoff-users/