How to set first success instance dependency for another job have multiple schedule

[Inaganti Ramesh]

How to set first success instance dependency for another job have multiple schedule.

JobA

JobB have below condition 

Condition: S(JobA) OR F(JobA)

If jobA fail , JobB will trigger

If JobA fail and took manul action then it got success( 2nd attempt ). JobB triggered again 2nd time.

I don't want JobB run second time when JobA take manual action for success(2nd instance)

Is there any way condition look for only first instance of jobA status ? Or like 2nd instance of job status 

[Alexander Liskow]

Hi,

if You want every Job to run only once, then You could put both jobs into a Box.

By default a Box expects every job in it to run once for the Box to receive a Success Event.

Define a Success Condition in the Box for JobB. This will create the success event for the Box even when JobA fails.

The jobchain of JobA and JobB is started by starting the Box.

A manual interaction on JobA has to be done with a Force Start event. 

However as the box is not in Running State the 2nd execution of JobA will NOT trigger JobB

[Michael Woods]

Hi,

It sounds like JobB may not be dependent on JobA if it can run on success or failure.  Could it just have the same starting condition as JobA so that it only runs once?

Mike

[Scott Fenton]

I may have missed the nuance here but I wanted to add to what others have said.

Instead of using S(JobA) or F(JobA) maybe use D(JobA) instead?

That will trigger when JobA is done, reaching a valid end state. This may give you what you need. Unfortunately have a job depend on success of itself only really works if that job isn't in a box, otherwise I would second the earlier recommendation on this. If this is a top-level object then that would work as well.

Best of luck!
Scott


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